9x^2-120x-68=0

Solution for 9x^2-120x-68=0 equation:

9x^2-120x-68=0

a = 9; b = -120; c = -68;
Δ = b2-4ac
Δ = -1202-4·9·(-68)
Δ = 16848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16848}=\sqrt{1296*13}=\sqrt{1296}*\sqrt{13}=36\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-36\sqrt{13}}{2*9}=\frac{120-36\sqrt{13}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+36\sqrt{13}}{2*9}=\frac{120+36\sqrt{13}}{18}
$